Let's take another example. However this time we will have multiplication instead of addition.
The final result is 0. Let's put some puts statements to debug this.
We can see that the very first time result is 0 and element is 2.
Multiplying anything with zero will result in zero. Question is why resutl is 0
the very first time.
The value of result for the for very time is passed in the inject method.
In this case see we are passing 0 in inject(0).
In the previous lesson we were doing addition so passing 0 as the starting value of result was ok.
However this time we are doing multiplication so we should change the value to 1.
For the first iteration the value of result is 1 and the value of element is 2. The returned value is 1 * 2 which is 2. Now 2 is the new value of result.
For the second iteration the value of result is 2 and the value of element is 3. The returned value is 2 * 3 which is 6. Now 6 is the new value of result.
For the third iteration the value of result is 6 and the value of element is 4. The returned value is 6 * 4 which is 24. Now 24 is the new value of result.
For the fourth iteration the value of result is 24 and the value of element is 5. The returned value is 24 * 5 which is 120. Now 120 is the new value of result.
Since all elements are used up the final value of the whole operation is 120.